Mathematicians read this!

[Optics]

I'm given this equation:

f(x)=3x²

I need to find:

- Vertex
- Transformation for ... a= ..... h= ....... k=.........
- y-intercept
- zeros , if applicable
- a point left and right of the vertex on the quadratic

If anyone could solve and do this for me I would appreciate it, theirs 35 more questions like this I will be tackling on my own.

 

[Wale_mybb_import14682]

I haven't done this in ages but I'll give it a try.
Vertex: (0,0)
Transformation: You could either say it stretches the y axis by a factor of 3 or in another way express that being on the x or y. I've never seen the transformation be written in a form of a, h, or k. If they want you to write it in intercept form it would be y= 3(x)^2 which is the exact same. A=3, h=0, k=0.
Y intercept= (0,0)
X intercept= (0,0
The zero is 0.
P.L= (-1,3)
P.R= (1,3)

 

[fatMatch]

I haven't done this shit since the beginning of the school year, almost time to start reviewing for finals -.-
Thank you for the reminder. :S