Daniel said:Don't know what this is but, WolfRamAlpha ftw
But just for the first one, I don't know what the #2 or 3 are. Oh well, going back to school again tomorrow, will probably see this later in like a week.
Deathcrow said:Just so you know how to actually solve the first one, it isn't that hard. They are factorials. For example, 5! is the same thing as saying 5*4*3*2*1. And 3! is the same thing as 3*2*1.
So to solve the first one you simply do:
(8*7*6*5*4*3*2*1)/((6*5*4*3*2*1)*(2*1)) = 40320/1440 = 28.
Daniel said:Deathcrow said:Just so you know how to actually solve the first one, it isn't that hard. They are factorials. For example, 5! is the same thing as saying 5*4*3*2*1. And 3! is the same thing as 3*2*1.
So to solve the first one you simply do:
(8*7*6*5*4*3*2*1)/((6*5*4*3*2*1)*(2*1)) = 40320/1440 = 28.
My canadian teacher would have taken probably 2 classes to teach us that. Thanks, learned something today.
Deathcrow said:Just so you know how to actually solve the first one, it isn't that hard. They are factorials. For example, 5! is the same thing as saying 5*4*3*2*1. And 3! is the same thing as 3*2*1.
So to solve the first one you simply do:
(8*7*6*5*4*3*2*1)/((6*5*4*3*2*1)*(2*1)) = 40320/1440 = 28.
Gengar said:Deathcrow said:Just so you know how to actually solve the first one, it isn't that hard. They are factorials. For example, 5! is the same thing as saying 5*4*3*2*1. And 3! is the same thing as 3*2*1.
So to solve the first one you simply do:
(8*7*6*5*4*3*2*1)/((6*5*4*3*2*1)*(2*1)) = 40320/1440 = 28.
Do you have any idea about the other 2?
Daniel said:Gengar said:Deathcrow said:Just so you know how to actually solve the first one, it isn't that hard. They are factorials. For example, 5! is the same thing as saying 5*4*3*2*1. And 3! is the same thing as 3*2*1.
So to solve the first one you simply do:
(8*7*6*5*4*3*2*1)/((6*5*4*3*2*1)*(2*1)) = 40320/1440 = 28.
Do you have any idea about the other 2?
Well, you can type in C_3 in WolfRamAlpha and it will interpret it as the C with the little 3 below it, but I don't know how you would put the other 6, _6C_3 doesn't work.
Gengar said:Deathcrow said:Just so you know how to actually solve the first one, it isn't that hard. They are factorials. For example, 5! is the same thing as saying 5*4*3*2*1. And 3! is the same thing as 3*2*1.
So to solve the first one you simply do:
(8*7*6*5*4*3*2*1)/((6*5*4*3*2*1)*(2*1)) = 40320/1440 = 28.
Do you have any idea about the other 2?
I love you. Please make children with me in the near future.Deathcrow said:Gengar said:Deathcrow said:Just so you know how to actually solve the first one, it isn't that hard. They are factorials. For example, 5! is the same thing as saying 5*4*3*2*1. And 3! is the same thing as 3*2*1.
So to solve the first one you simply do:
(8*7*6*5*4*3*2*1)/((6*5*4*3*2*1)*(2*1)) = 40320/1440 = 28.
Do you have any idea about the other 2?
6C3 = [6!/(6-3)!*3!] = 6!/[3!*3!] = 20.
7P2 = 7!/(7-2)! = 7!/5! = 42.
Gengar said:I love you. Please make children with me in the near future.Deathcrow said:Gengar said:Do you have any idea about the other 2?
6C3 = [6!/(6-3)!*3!] = 6!/[3!*3!] = 20.
7P2 = 7!/(7-2)! = 7!/5! = 42.
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