Algebra

Imma work on that, gimme some time

@edit

do you need that for today? I can take that to the university tomorrow and ask for a teacher to do it :3
 
Worms said:
Imma work on that, gimme some time

@edit

do you need that for today? I can take that to the university tomorrow and ask for a teacher to do it :3
Click to expand...

I'd love you forever if you could do it today, or at least guide me in the right direction to solve it because this is a take home test and this is the last question I need and I'd be happy if I could turn it in tomorrow. Although it is due Saturday 11:59pm.
 
Hahahaha im pretty good at math but unfortunatly im only on my first year of Comp Science, im trying to figure out how to do that, imma talk to some friends

@edit: I think i got something here

Add me on skype lets talk this through i think i made it
 
Worms said:
Hahahaha im pretty good at math but unfortunatly im only on my first year of Comp Science, im trying to figure out how to do that, imma talk to some friends

@edit: I think i got something here
Click to expand...

Well I know that f(x) = sqr(x) will have these values



And look like this too:



And I also know that if it is
the graph or w/e will be shifted right h and up k, but can't get past there and can't figure out the numbers <.<

Edit: added
 
The square root must produce an integer for both 3 and 8. 3 - -1 = 4 - -1 = 9, 2 perfect squares. h = -1. a = 2, k = 0. for n = 2.
 
Deathwish said:
The square root must produce an integer for both 3 and 8. 3 - -1 = 4 - -1 = 9, 2 perfect squares. h = -1. a = 2, k = 0. for n = 2.
Click to expand...

Yes thats what i found out hahaa, thanks for posting it i was gonna do it now


@daniel

that SQRR function will not help you, you need to look at the given one. A tip for you, its easier to find H first, thane try other values to A and K
 
I figured that k is always 0 by making simultaneous equations then subtracting, don't know if it's actually true until I get something.

I've got another one - h = 5.06 a = -.74 k = 0 <- for cubic
 
Deathwish said:
I figured that k is always 0 by making simultaneous equations then subtracting, don't know if it's actually true until I get something.
Click to expand...

I think we can't assume that cause maybe both equations need +1 to be equal the given X and Y.

BUT if you have only 2 equations probalby k = 0 on all of them so you only have to find 2 numbers.
 
Deathwish said:
I messed up some negative signs, try h = 1 a = 3.06 k = .15
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for which one? n=3 or n=4?
 
DAMN IT DANIEL IXDREAMSXI I THOUGHT WE WERE ALREADY CONTACTS and n=3, I like to go in order
 
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