1=2: A Proof using Beginning Algebra

jolito098 · Jul 29, 2011

The Fallacious Proof:
Step 1: Let a=b.
Step 2: Then

Step 3:

Step 4:

Step 5:

Step 6: and

Step 7: This can be written as ,

Step 8: and cancelling the

from both sides gives 1=2.

Lol!

See if you can figure out in which step the fallacy lies.
Post your guesses here!!D

rahul_mybb_import17594 · Jul 29, 2011

nice one.
Hey are you intrested in maths, well i hate mathematics, its so boring and its not easy for solving maths sums.

jolito098 · Jul 30, 2011

lol
i love mathematics. But these ae just simple calculations so anyone who have undergone Algebra would understand this and could tell where is the fallacy there.

rahul_mybb_import17594 · Jul 30, 2011

jolito098 said:
lol
i love mathematics. But these ae just simple calculations so anyone who have undergone Algebra would understand this and could tell where is the fallacy there.

hmm... i remember i was solved these kind of sums in 8th, 10th and 12th standard

Triapod · Jul 30, 2011

Problem is you can't cancel out the (a^2 - ab) because that means you divided both sides by this value but since a=b, (a^2-ab)=0 and you can't divide by zero

jolito098 · Jul 30, 2011

Triapod said:
Problem is you can't cancel out the (a^2 - ab) because that means you divided both sides by this value but since a=b, (a^2-ab)=0 and you can't divide by zero

Good job!!
You're actually right. Please edit your post and put it in spoiler so that no one could cheat

1=2: A Proof using Beginning Algebra

jolito098

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1=2: A Proof using Beginning Algebra

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